HackerRank Python: Python If-Else Solution

Table of Contents

Question

Task
Given an integer, , perform the following conditional actions:

If n is odd, print Weird
If n is even and in the inclusive range of 2 to 5 , print Not Weird
If n is even and in the inclusive range of 6 to 20 , print Weird
If n is even and greater than 20 , print Not Weird

Input Format

A single line containing a positive integer, .

Constraints

1 ≤ n ≤ 100

Output Format

Print Weird if the number is weird. Otherwise, print Not Weird.

Sample Input 0

Sample Output 0

Weird

Explanation 0

is odd and odd numbers are weird, so print Weird.

Sample Input 1

Sample Output 1

Not Weird

Explanation 1

n = 24

n > 20 and n is even, so it is not weird.

Solution

				
					n = int(input().strip())

if n % 2 != 0:
    print("Weird")
elif n in range(2, 6):
    print("Not Weird")
elif n in range(6, 21):
    print("Weird")
else:
    print("Not Weird")

Explanation

The code takes a single line input, n, as a positive integer and performs the following conditional actions:

If n is odd (n % 2 != 0), it prints “Weird”.
If n is even (n % 2 == 0):
- If n is in the inclusive range of 2 to 5 (n in range(2, 6)), it prints “Not Weird”.
- If n is in the inclusive range of 6 to 20 (n in range(6, 21)), it prints “Weird”.
- If n is greater than 20, it prints “Not Weird”.